…there might be other reasons too…
Exploring The Lemmy Archipelago 🏝️🍾
…there might be other reasons too…
Lukoshenko did say that Prigozhin is moving freely in Russia, as opposed to staying in Belarus, as negotiated. Something might be brewing.
Oh. I’m mainly using the browser for pretty much everything.
I think Memmy, an iOS client that released just today or yesterday, allows you to.
You can see content without an account. Unless it’s NSFW, I guess.
All your server are belong to us 🤖
Interesting to hear this from a dirty lemmy.fmhy.ml-er! 😈
He was free()
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These are upvotes and downvotes. I doubt views are logged anywhere, apart from the webserver.
Why are you selecting for long names? 😅
Makes sense. I also use all kinds of messengers. But it just so happens that the people I communicate with the most also use Signal 😁
In terms of an optimal load spread, it’s best if the lemmiverse is split into multiple equally sized instances. If you use an instance just for yourself, it doesn’t actually decrease the load on the main servers in any way. The only thing you get is a guarantee that your instance won’t suddenly go down.
I guess chefs have homes too
Embrace your true self
Maybe people should realise that they, too, have a life, just like Musk-Trump-West-Rogan-Peterson-Shapiro-Kardashians.
Some people on the internet live in a very detached reality… 😅
You did see this coming, but I don’t understand why people associate Telegram with security in any way. It openly states that it’s not end to end encrypted and everything is visible to the server! And if you enable end to end encryption for a particular chat, its functionality is severely restricted.
That’s some serious dedication to making a dinner…
Are there any people left who use just 1 app for messaging? There’s WhatsApp, Messenger, Instagram, Signal, Telegram, Viber, WeChat, Snapchat, Discord, Slack, Line, etc, etc. And these are just the main ones.
I’d be fine with using it as my messenger of choice if they open sourced it and allowed us to run our own servers
E = mc^2 🤯